Home
Class 12
PHYSICS
A ball after having fallen from rest und...

A ball after having fallen from rest under the influence of gravity for 6 s crashes through a horizontal glass plate, thereby losing two-third of its velocity. It then reaches the ground in 2 s, find the height of the plate above the ground.

Text Solution

AI Generated Solution

To solve the problem step by step, we will break it down into parts: ### Step 1: Calculate the velocity of the ball just before it hits the glass plate. The ball falls from rest under the influence of gravity for 6 seconds. We can use the first equation of motion: \[ v = u + gt \] where: ...
Promotional Banner

Topper's Solved these Questions

  • Motion in Straight Line

    VMC MODULES ENGLISH|Exercise SOLVED EXAMPLES|20 Videos

  • Motion in Straight Line

    VMC MODULES ENGLISH|Exercise PRACTICE EXERCISE|80 Videos

  • MOTION IN A STRAIGHT LINE & PLANE

    VMC MODULES ENGLISH|Exercise IMPECCABLE|52 Videos

  • Motion in Two Dimensions

    VMC MODULES ENGLISH|Exercise MCQ|2 Videos

Similar Questions

Explore conceptually related problems

A stone released with zero velocity from the top of a tower, reaches the ground in 4s. The height of the tower is (g = 10 m//s^(2))

Two balls are projected simultaneously with the same speed from the top of a tower-one upwards and the other downwards.If they reach the ground in 6s and 2s ,the height of the tower is

A ball projected upwards from the foot of a tower. The ball crosses the top of the tower twice after an interval of 6 s and the ball reaches the ground after 12 s . The height of the tower is (g = 10 m//s^2) :

A ball projected upwards from the foot of a tower. The ball crosses the top of the tower twice after an interval of 6 s and the ball reaches the ground after 12 s . The height of the tower is (g = 10 m//s^2) :

A body projected up reaches a point A in its path at the end of 4th second and reaches the ground after 5 seconds from the start. The height of A above the ground is (g=10 "m/s"^2)

A ball is thrown upward with speed 10 m/s from the top to the tower reaches the ground with a speed 20 m/s. The height of the tower is [Take g=10m//s^(2) ]

A body falls freely under gravity from rest and reaches the ground in time t. Write an expression for the height fallen by the body.

A stone is dropped from a rising balloon at a height of 76 m above the ground and reaches the ground in 6s. What was the velocity of the balloon when the stone was dropped?

A ball is thrown vertically upwards from the top of a tower with an initial velocity of 19.6 m s^(-1) . The ball reaches the ground after 5s. Calculate the height of the tower .

A body is thrown horizontally from the top of a tower. It reaches the ground after 4s at an angle 45° to the ground. The velocity of projection is