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A ball is released from the top of a tow...

A ball is released from the top of a tower of height h metre. It takes T second to reach the ground. What is the position of the ball in `T/3` second?

Text Solution

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Using `y=ut +(1)/(2)" gt"^(2)`, we get
? `h=0+(1)/(2)" gt"^(2)" or "gT^(2)=2h`
Now, distance moved in time T/3 is `y=(1)/(2) g (T^(2))/(3) =(gT^(2))/(2xx9)" or, "y=(2h)/(2xx9) =(h)/(9)`
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