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A boy playing on the roof of a 10 m high...

A boy playing on the roof of a `10 m` high building throws a ball with a speed of `10 m//s` at an angle of `30^(@)` with the horizontal. How far from the throwing point will the ball be at the height of `10 m` from the ground ?
`[ g = 10m//s^(2) , sin 30^(@) = (1)/(2) , cos 30^(@) = (sqrt(3))/(2)]`

Text Solution

Verified by Experts

Horizontal range of projectile
`R=(u^(2) sin 20)/(g) =((10)^(2) sin 60^(@))/(10) =10 xx (sqrt(3))/(2) =8.66 m`
Thus, the distance of point Q from the P as shown in figure is 8.66 m.
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