Home
Class 12
PHYSICS
A ball is thrown from the ground so that...

A ball is thrown from the ground so that it just crosses a wall 5m high at a distance of 10m and falls at a distance of 10m ahead from the wall. Find the speed and the direction of projection of ball. Assume, `g = 10" ms"^(–2)`

Text Solution

AI Generated Solution

To solve the problem of a ball thrown from the ground that just crosses a wall 5m high at a distance of 10m, and then falls 10m ahead of the wall, we can follow these steps: ### Step 1: Understand the problem We need to find the initial speed \( u \) and the angle of projection \( \theta \) of the ball. The wall height \( H = 5 \, m \), the horizontal distance to the wall \( x = 10 \, m \), and the total horizontal distance from the throw point to where the ball lands is \( 20 \, m \). ### Step 2: Use the equations of motion The maximum height \( H \) reached by the projectile can be given by the formula: \[ ...
Promotional Banner

Topper's Solved these Questions

  • Motion in Straight Line

    VMC MODULES ENGLISH|Exercise SOLVED EXAMPLES|20 Videos

  • Motion in Straight Line

    VMC MODULES ENGLISH|Exercise PRACTICE EXERCISE|80 Videos

  • MOTION IN A STRAIGHT LINE & PLANE

    VMC MODULES ENGLISH|Exercise IMPECCABLE|52 Videos

  • Motion in Two Dimensions

    VMC MODULES ENGLISH|Exercise MCQ|2 Videos

Similar Questions

Explore conceptually related problems

A ball is thrown from ground level so as to just clear a wall 4 m high at a distance of 4 m and fall at a distance of 14 m from the wall. Find the magnitude and direction of the velocity of the ball.

A ball is thrown from the ground to clear a wall 3 m high at a distance of 6 m and falls 18 m away from the wall. Find the angle of projection of ball.

A ball is thrown from the ground to clear a wall 3 m high at a distance of 6 m and falls 18 m away from the wall. Find the angle of projection of ball.

A 15 m long ladder reached a window 12 m highfrom the ground on placing it against a wall at a distance a. Find the distance of the foot of theladder from the wall.

A ball is thrown upwards from the ground with an initial speed of u. The ball is at height of 80m at two times, the time interval being 6 s. Find u. Take g=10 m//s^2.

A ball is thrown from the top of a tower with an initial velocity of 10 m//s at an angle of 30^(@) above the horizontal. It hits the ground at a distance of 17.3 m from the base of the tower. The height of the tower (g=10m//s^(2)) will be

A ball is thrown upwards from the top of a tower 40 m high with a velocity of 10 m//s. Find the time when it strikes the ground. Take g=10 m//s^2 .

A ball is thrown upwards from the top of a tower 40 m high with a velocity of 10 m//s. Find the time when it strikes the ground. Take g=10 m//s^2 .

From the top of a tower, 80m high from the ground a stone is thrown in the horizontal direction with a velocity of 8 ms^(1) . The stone reaches the ground after a time t and falls at a distance of d from the foot of the tower. Assuming g=10ms^(2) , the time t and distance d are given respectively by

A ball is thrown from ground such that it just crosses two poles of equal height kwpt 80 m apart. The maximum height attained by the ball is 80 m. When the ball passes the first pole, its velocity makes 45^(@) with horizontal. The correct alternatives is/are :- (g=10 m//s^(2))