Home
Class 12
PHYSICS
Two moving particles P and Q are 10cm ap...

Two moving particles `P` and `Q` are 10cm apart at any instant. Velocity of P is `8 m//s` at `30^(@)`, from line joining the P and Q and velocity of Q is `6m//s` at `30^(@)`. Calculate the angular velocity of P w.r.t. Q

Text Solution

Verified by Experts

`X_(P//Q) =(8 sin 30^(@))-(-6 sin 30^(@))/(10)=0.7" rad/s"`
Promotional Banner

Topper's Solved these Questions

  • Motion in Straight Line

    VMC MODULES ENGLISH|Exercise SOLVED EXAMPLES|20 Videos

  • Motion in Straight Line

    VMC MODULES ENGLISH|Exercise PRACTICE EXERCISE|80 Videos

  • MOTION IN A STRAIGHT LINE & PLANE

    VMC MODULES ENGLISH|Exercise IMPECCABLE|52 Videos

  • Motion in Two Dimensions

    VMC MODULES ENGLISH|Exercise MCQ|2 Videos

Similar Questions

Explore conceptually related problems

Two particles P and Q are moving as shown in the figure. At this moment of time the angular speed of P w.r.t. Q is

Two particles P and Q are projected simultaneously away from each other from a point A as shown in figure. The velocity of P relative to Q in ms^(-1) at the instant when the motion of P is horizontal is

Two particles P and Q are moving on circle. At a certain instant of time both the particles and diametrically opposite and P has tangential acceleration 8 m//s^(2) and centripetal acceleration 5 m//s^(2) whereas Q has only e centripetal acceleration of 1 m//s^(2) . At that instant acceleration ("in" m//s^2) of P with respect to Q is

The displacement-time graphs of two particles P and Q are as shown in the figure. The ratio of their velocities V_P and V_Q will be

A particle is moving in a circle of radius r with speed v as shown in the figure. The magnitude of change in velocity in moving from P to Q is

A particle is moving in a circle of radius r with speed v as shown in the figure. The magnitude of change in velocity in moving from P to Q is

Two particles P and Q simultaneously start moving from point A with velocities 15 m//s and 20 m//s respectively. The two particles move with acceleration equal in magnitude but opposite in direction. When P overtakes Q at point B then its velocity is 30 m//s , the velocity of Q at point B will be

A particle P is projected with speed 20 m//s at angle 37^(@) from horizontal as shown in figure, At the some instant Q starts from same point and moves with uniform acceleration towards right. Path of the particle P w.r.t. Q is straight line Acceleration of Q is : .

A particle slides with a speed of 3m s^(-1) at P. When it reaches Q ,it acquires a speed of 4m s^(-1) after describing an angle of 60^(@) at O as shown in figure .Find the changes in the velocity of the particle between P and Q . Assume that the path followed by the particle is circular from P to Q

A two particles P and Q are separated by distance d apart. P and Q move with velocity v and u making an angle 60^@ and theta with line PQ the graph between their relative separation (8) when time t is shown in figure (2). The velocity v in terms of u