A particle is dropped from the top of a tower. Its covered distance in last 1 sec is equal to distance covered by particle in `1^(st) 3s`. Find height of tower.

Explanation

To solve the problem step by step, let's break it down:

### Step 1: Understand the problem
A particle is dropped from the top of a tower. We need to find the height of the tower given that the distance it covers in the last second of its fall is equal to the distance it covers in the first three seconds of its fall.

### Step 2: Define the variables
Let:
- \( h \) = height of the tower
...