A ball is thrown at angle `theta` and another ball is thrown at an angle `(90^(@)-theta)` with the horizontal direction from the same point with velocity `39.2 ms^(-1)`. The second ball reaches 50 m higher than the first ball. Find their individual heights. Take `g = 9.8 ms^(-2)`.

Explanation

To solve the problem, we need to find the individual heights \( h_1 \) and \( h_2 \) of two balls thrown at angles \( \theta \) and \( 90^\circ - \theta \) respectively, with the second ball reaching 50 meters higher than the first.

### Step-by-Step Solution:

1. **Understanding the Problem**:
- We have two balls thrown from the same point with the same initial velocity \( v = 39.2 \, \text{m/s} \).
- The first ball is thrown at an angle \( \theta \) and the second at an angle \( 90^\circ - \theta \).
- The height of the second ball \( h_2 \) is 50 meters higher than the height of the first ball \( h_1 \):
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