The range of a projectile, when launched at an angle of ` 15^(@)` with the horizontal is 1.5 km. what is the range of the projectile, when launched at an angle of ` 45^(@)` to the horizontal with the same speed ?

Explanation

To solve the problem, we will use the formula for the range of a projectile, which is given by:

\[ R = \frac{u^2 \sin 2\theta}{g} \]

where:
- \( R \) is the range,
- \( u \) is the initial velocity,
- \( \theta \) is the angle of projection,
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