The second's hand of a watch has length 6 cm. Speed of end point and magnitude of difference of velocities at two perpendicular positions will be

Options

A. 2n & 0 mm/s
B. `2 sqrt(2) n & 4.44` mm/s
C. `2 sqrt(2) n & 2` n mm/s
D. `2 n & 2 sqrt(2)` n mm/s

Explanation

To solve the problem step by step, we need to find the speed of the endpoint of the second's hand of a watch and the magnitude of the difference of velocities at two perpendicular positions.

### Step 1: Identify the parameters
The length of the second's hand (which acts as the radius of the circular path) is given as:
- Length (L) = 6 cm

### Step 2: Convert length to meters
Since we need the speed in millimeters per second, we can convert the length from centimeters to meters:
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