A stone tied to the end of a string 80 cm long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolutions in 25 s, the magnitude of acceleration is :

Options

A. `20" ms"^(-2)`
B. `12" ms"^(-2)`
C. `9.9" ms"^(-2)`
D. `8" ms"^(-2)`

Explanation

To solve the problem step by step, let's follow the outlined process:

### Step 1: Understand the problem
We have a stone tied to a string of length 80 cm, which is being whirled in a horizontal circle. The stone completes 14 revolutions in 25 seconds. We need to find the magnitude of the acceleration of the stone.

### Step 2: Convert the length of the string to meters
The length of the string (radius of the circular path) is given in centimeters. We need to convert it to meters for consistency in our calculations.

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