A particle starts moving along a circle of radius `(20//pi)m` with constant tangential acceleration. If the velocity of the parthcle is `50 m//s` at the end of the second revolution after motion has began, the tangential acceleration in `m//s^(2)` is :

Options

A. `1.6`
B. 4
C. `15.6`
D. `13.2`

Explanation

To solve the problem, we need to find the tangential acceleration of a particle moving in a circular path with a given radius and final velocity after a certain number of revolutions. Let's break it down step by step.

### Step 1: Identify the given data
- Radius of the circle, \( r = \frac{20}{\pi} \) m
- Final velocity after 2 revolutions, \( v = 50 \) m/s
- Initial velocity, \( u = 0 \) m/s (since the particle starts from rest)
- Number of revolutions, \( n = 2 \)

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