Home
Class 12
PHYSICS
If the position vector of a particle is ...

If the position vector of a particle is `vecr=(3hati+4hatj)` meter and Its angular velocity is `vecomega(hatj+2hatk)` rad/sec then find its linear velocity(in m/s)?

Text Solution

AI Generated Solution

To find the linear velocity of the particle given its position vector and angular velocity, we can use the formula: \[ \vec{v} = \vec{\omega} \times \vec{r} \] where: - \(\vec{v}\) is the linear velocity, ...
Promotional Banner

Topper's Solved these Questions

  • SYSTEM OF A PARTICLES & ROTATIONAL MOTION

    VMC MODULES ENGLISH|Exercise PRACTICE EXERCISE-3|5 Videos

  • SYSTEM OF A PARTICLES & ROTATIONAL MOTION

    VMC MODULES ENGLISH|Exercise PRACTICE EXERCISE-4|7 Videos

  • SYSTEM OF A PARTICLES & ROTATIONAL MOTION

    VMC MODULES ENGLISH|Exercise PRACTICE EXERCISE-1|4 Videos

  • SIMPLE HARMONIC MOTION

    VMC MODULES ENGLISH|Exercise 7-previous year question|46 Videos

  • SYSTEM OF PARTICLES AND ROTATIONAL MOTION

    VMC MODULES ENGLISH|Exercise IMPECCABLE|56 Videos

Similar Questions

Explore conceptually related problems

If angular velocity of a particle having position vector vec r = (2hati - 2hatj + 2hatk)m about the origin is vec w = (2hati - 2hatj - hatk)rad/s then magnitude of linear velocity of the particle will be

The position of a particle is given by vecr=(hati+2hatj-hatk) and momentum vecp=(3hati+4hatj-2hatk) . The angular momentum is perpendicular to the

If vecomega=2hati-3hatj+4hatk and vecr=2hati-3hatj+2hatk then the linear velocity is

The angular velocity of a particle is vec(w) = 4hati + hatj - 2hatk about the origin. If the position vector of the particle is 2hati + 3hatj - 3hatk , then its linear velocity is

If the position vector of one end of the line segment AB be 2hati+3hatj-hatk and the position vector of its middle point be 3(hati+hatj+hatk) , then find the position vector of the other end.

If the velocity of a particle is (2hati+3hatj-4hatk) and its acceleration is (-hati+2hatj+hatk) and angle between them in (npi)/(4) . The value of n is .

If angular velocity of a point object is vecomega=(hati+hat2j-hatk) rad/s and its position vector vecr=(hati+hatj-5hatk) m then linear velocity of the object will be

The velocity of a particle is v=6hati+2hatj-2hatk The component of the velocity parallel to vector a=hati+hatj+hatk in vector from is

What is the value of linear velocity, if vecomega=3hati-4hatj+hatk and vecr=5hati-6hatj+6hatk ?

What is the value of linear velocity, if vecomega=3hati-4hatj+hatk and vecr=5hati-6hatj+6hatk ?