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The n rows each containing m cells in series are joined in parallel. Maximum current is taken from this combination across anexternal resistance of `3Omega` resistance. If the total number pf cell used are 24 and internal resistance of each cell is `0.5Omega`, then

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Total number of cell mn=24
For maximum current when`(mr)/(n)`=R (using maximum power transfer theorem)
`rArr`   0.5m=3n
`rArr`     m=`(3n)/(0.5)`=6n 
`therefore`   `6nxxn`=24    `rArr`     n=2 
and `mxx2`=24 `rArr`     m=12
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