Three identical cells, each of emf 2 V and internal resistance `0.2Omega` are connected in series to an external resistor of `7.4Omega`. Calculate the current in the circuit.

24 cells, each of emf 1.5V and internal resistance is 2Omega connected to 12Omega series external resistance. Then,

Three identical cells each of emf 2 V and internal resistance 1 Omega are connected in series to form a battery. The battery is then connected to a parallel combination of two identical resistors, each of resistance 6 Omega Find the current delivered by the battery.

A set of 4 cell each of emf 2V and internal resistance 1.5 Omega are connected across an external load of 10 Omega with 2 rows, two cells in each row. Calculate the current in each row and potential difference across 10 Omega

n identical cells each of e.m.f. E and internal resistance r are connected in series. An external resistance R is connected in series to this combination. The current through R is

Two cells having emf's of 10 V and 8 V, and internal resistance of 1Omega (each) are connected as shown with an external resistance of 8Omega Find the current flowing through the circuit.

There are n cells, each of emf E and internal resistance r, connected in series with an external resistance R. One of the cells is wrongly connected, so that it sends current in the opposite direction. The current flowing in the circuit is

Three identical cells , each having an emf 1.5 V and a constant internal resistance 2.0 ohm , are connected in series with a 4.0 ohm resistor R, first as in circuit (i) , and second as in circuit (ii) . Then ( power in R in circuit (i))/( Power in R in circuit (ii)) =

Four cells, each of emf E and internal resistance r, are connected in series across an external resistance R. By mistake one of the cells is connected in reverse. Then, the current in the external circuit is

Find the current drawn from a cell of emf 2 V and internal resistance 2 Omega connected to the network given below.

Ten cells each of emf 1 V and internal resistance 1Omega are connected inseries. In this arrangement, polarity of two cells is reversed and the system is connected to an external resistance of 2Omega . Find the current in the circuit.