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Two straight parallel wires, both carryi...

Two straight parallel wires, both carrying `10` ampere in the same direction attract each other with a force of `1xx10^(-3)N`. If both currents are doubled, the force of attraction will be

A

`1xx10^(3)N`

B

`2xx10^(3)N`

C

`4xx10^(3)N`

D

`0.25xx10^(3)N`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will use the formula for the force between two parallel current-carrying wires. The force \( F \) between two parallel wires carrying currents \( I_1 \) and \( I_2 \) separated by a distance \( r \) is given by: \[ F = \frac{{\mu_0 I_1 I_2 L}}{{2 \pi r}} \] Where: - \( F \) is the force between the wires, - \( \mu_0 \) is the permeability of free space, - \( I_1 \) and \( I_2 \) are the currents in the wires, - \( L \) is the length of the wires, - \( r \) is the distance between the wires. ### Step-by-Step Solution: 1. **Identify the initial values:** - Given that both wires carry a current of \( I_1 = I_2 = 10 \, \text{A} \). - The initial force \( F \) is \( 1 \times 10^{-3} \, \text{N} \). 2. **Determine the effect of doubling the currents:** - If both currents are doubled, then: \[ I_1' = 2 \times I_1 = 2 \times 10 \, \text{A} = 20 \, \text{A} \] \[ I_2' = 2 \times I_2 = 2 \times 10 \, \text{A} = 20 \, \text{A} \] 3. **Substitute the new currents into the force equation:** - The new force \( F' \) can be calculated as: \[ F' = \frac{{\mu_0 I_1' I_2' L}}{{2 \pi r}} = \frac{{\mu_0 (20)(20) L}}{{2 \pi r}} \] 4. **Relate the new force to the original force:** - Since the original force was: \[ F = \frac{{\mu_0 (10)(10) L}}{{2 \pi r}} = \frac{{\mu_0 (100) L}}{{2 \pi r}} \] - The new force can be expressed in terms of the original force: \[ F' = \frac{{\mu_0 (20)(20) L}}{{2 \pi r}} = \frac{{\mu_0 (400) L}}{{2 \pi r}} = 4 \times \frac{{\mu_0 (100) L}}{{2 \pi r}} = 4F \] 5. **Calculate the new force:** - Since \( F = 1 \times 10^{-3} \, \text{N} \): \[ F' = 4 \times (1 \times 10^{-3}) = 4 \times 10^{-3} \, \text{N} \] ### Final Answer: The new force of attraction when both currents are doubled is \( 4 \times 10^{-3} \, \text{N} \).
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