Home
Class 12
PHYSICS
The magnetic flux across a loop of resis...

The magnetic flux across a loop of resistance `10Omega` is given by `phi=5t^(2)-4t+1Wb`. How much current is induced in the loop after `0.2` s?

A

0.4A

B

0.2A

C

0/04A

D

0.02A

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-B|10 Videos

  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-C|10 Videos

  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    VMC MODULES ENGLISH|Exercise PRACTICE EXERCISE 5|5 Videos

  • DYNAMICS OF A PARTICLE

    VMC MODULES ENGLISH|Exercise JEE Advance (Archive) Level - II (SINGLE OPTION CORRECT TYPE )|31 Videos

  • ELECTROMAGNETIC INDUCTION & ALTERNATIVE CURRENT

    VMC MODULES ENGLISH|Exercise IMPECCABLE|52 Videos

Similar Questions

Explore conceptually related problems

The magnetic flux linked with a coil (in Wb) is given by the equation phi = 5t^2 + 3t +16 . The magnetic of induced emf in the coil at fourth second will be

The magnetic flux linked with a coil, in webers is given by the equation phi=3t^(2)+4t+9 . Then, the magnitude of induced emf at t = 2 s

A time varying magnetic flux passing through a coil is given by phi=xt^(2) , if at t=3s , the emf induced is 9 V, then the value of x is

A plane loop, shaped as two squares of sides a = 1m and b = 0.4m is introduced into a uniform magnetic field _|_ to the plane of loop . The magnetic field varies as B = 10(-3)sin(100t) T . The qamplitude of the current induced in the loop if its resistance per unit length is r = 5 mOmega m^(-1) is

The flux of magnetic field through a closed conducting loop of resistance 0.4 Omega changes with time according to the equation Phi =0.20 t^(2)+0.40t+0.60 where t is time in seconds.Find (i)the induced emf at t=2s .(ii)the average induced emf in t=0 to t=5 s .(iii)charge passed through the loop in t=0 to t=5s (iv)average current.In time interval t=0 to t=5 s (v) heat produced in t=0 to t=5s

The magnetic flux through a coil perpendicluar to its plane and directed into paper is varying according to the relation phi=(2t^(2)+4t+6)mWb . The emf induced in the loop at t=4 s is

The magnetic flux (phi) in a closed circuit of resistance 20 Omega varies with time (t) according to the equation phi = 7t^(2) - 4t where phi is in weber and t is in seconds. The magnitude of the induced current at t =0.25s is

A circular loop is placed in magnetic field B=2t. Find the direction of induced current produced in the loop.

A square conductind loop, 20.0 cm on a side placed in the same magnetic field as shown in Fig. 3.195, center of the magnetic field region, where dB//dt = 0.035 T s^(-1) . The current induced in the loop if its resistance is 2.00 Omega is

The flux linked with a coil at any instant 't' is given by phi = 10t^(2) - 50t +250 The induced emf at t = 3s is