The magnetic field perpendicular to the plane of a loop of area `0.1m^(2)` is 0.2 T. Calculate the magnetic flux through the loop (in weber)

Options

A. 0.01
B. 0.02
C. 0.03
D. 0.04

Answer

To calculate the magnetic flux through the loop, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Area of the loop (A) = 0.1 m²
- Magnetic field (B) = 0.2 T
- Angle (θ) between the magnetic field and the area vector = 0° (since the magnetic field is perpendicular to the loop)

2. **Recall the Formula for Magnetic Flux:**
The magnetic flux (Φ) through a surface is given by the formula:
\[ Φ = B \cdot A \cdot \cos(θ) \]

3. **Substitute the Values into the Formula:**
Since the angle θ is 0°, we know that:
\[ \cos(0°) = 1 \]
Therefore, we can substitute the values into the formula:
\[ Φ = 0.2 \, \text{T} \cdot 0.1 \, \text{m}² \cdot \cos(0°) \]
\[ Φ = 0.2 \, \text{T} \cdot 0.1 \, \text{m}² \cdot 1 \]

4. **Calculate the Magnetic Flux:**
Now, perform the multiplication:
\[ Φ = 0.2 \cdot 0.1 = 0.02 \, \text{Weber} \]

5. **Final Result:**
The magnetic flux through the loop is:
\[ Φ = 0.02 \, \text{Weber} \]