The specific conductance of a salt of `0.05` M concentration is `1.061 xx10^(-4)" Scm"^(-1)` Molar conductance of the same solution will be:

Options

A. `1.061 xx 10^(-4) Omega^(-1)cm^(2)"mole"^(-1)`
B. `2.122 Omega^(-1)cm^(2)"mole"^(-1)`
C. `10.61 Omega^(-1)cm^(2)"mole"^(-1)`
D. `1.0 Omega^(-1)cm^(2)"mole"^(-1)`

Answer

To find the molar conductance (Λm) of a salt solution with a specific conductance (κ) of \(1.061 \times 10^{-4} \, \text{S cm}^{-1}\) and a concentration of \(0.05 \, \text{M}\), we can use the formula:

\[ \Lambda_m = \frac{\kappa \times 1000}{C} \]

where:
- \(Λ_m\) is the molar conductance,
- \(κ\) is the specific conductance,
- \(C\) is the molarity of the solution.

### Step-by-Step Solution

1. **Identify the given values**:
- Specific conductance (κ) = \(1.061 \times 10^{-4} \, \text{S cm}^{-1}\)
- Concentration (C) = \(0.05 \, \text{M}\)

2. **Substitute the values into the formula**:
\[ \Lambda_m = \frac{1.061 \times 10^{-4} \, \text{S cm}^{-1} \times 1000}{0.05} \]

3. **Calculate the numerator**:
\[ 1.061 \times 10^{-4} \times 1000 = 1.061 \times 10^{-1} = 0.1061 \, \text{S cm}^{-1} \]

4. **Now, divide by the concentration**:
\[ \Lambda_m = \frac{0.1061 \, \text{S cm}^{-1}}{0.05} \]

5. **Perform the division**:
\[ \Lambda_m = 0.1061 \div 0.05 = 2.122 \, \text{S cm}^{-1} \text{ mol}^{-1} \]

6. **Final Result**:
The molar conductance \(Λ_m\) is \(2.122 \, \text{S cm}^{-1} \text{ mol}^{-1}\).

### Conclusion
The molar conductance of the solution is \(2.122 \, \text{S cm}^{-1} \text{ mol}^{-1}\).

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