Isopropyl alcohol on oxidation forms :

Options

A. Acetone
B. Ether
C. Ethylene
D. Acetaldehyde

Answer

To determine the product formed when isopropyl alcohol is oxidized, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of Isopropyl Alcohol**:
- Isopropyl alcohol, also known as 2-propanol, has the molecular formula C3H8O. Its structure can be represented as:
\[ \text{CH}_3\text{CH(OH)}\text{CH}_3 \]
- This means there are three carbon atoms, with the hydroxyl (–OH) group attached to the second carbon.

2. **Understand the Oxidation Process**:
- Oxidation involves the removal of hydrogen atoms or the addition of oxygen. In the case of alcohols, primary and secondary alcohols can be oxidized to form aldehydes or ketones, respectively.
- Isopropyl alcohol is a secondary alcohol, which means it will be oxidized to form a ketone.

3. **Apply the Oxidizing Agent**:
- The oxidation is typically carried out using an oxidizing agent such as potassium dichromate (K2Cr2O7) in an acidic medium.
- During the oxidation of isopropyl alcohol, two hydrogen atoms (one from the hydroxyl group and one from the adjacent carbon) are removed.

4. **Determine the Product**:
- After the removal of the hydrogen atoms, the structure changes from isopropyl alcohol to a ketone. The resulting compound is:
\[ \text{CH}_3\text{C(=O)}\text{CH}_3 \]
- This compound is known as propanone, or acetone.

5. **Conclusion**:
- Therefore, the oxidation of isopropyl alcohol results in the formation of propanone (acetone).

### Final Answer:
Isopropyl alcohol on oxidation forms **propanone (acetone)**.

---