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The ratio of the radius difference betwe...

The ratio of the radius difference between `4^(th)` and `3^(rd)` orbit of H-atom and that of `Li^(2+)` ion is :

A

`1:1`

B

`3:1`

C

`3:4`

D

`9:1`

Text Solution

Verified by Experts

The correct Answer is:
B
`r_(4^(th))-r_(3^(rd)) = (a_0)/(Z) [4^2 - 3^2] therefore (r_(H^+))/(r_(Li^(2+))) = 3/1`
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