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In the following equation: 4FeS(2) + 11O...

In the following equation: `4FeS_(2) + 11O_(2) to 2Fe2O3 + 8SO2`. The volume of air measured at 1 atm and 273 K, used in oxidation of 6g `FeS_(2)` assuming that air contains 20% of oxygen by volume is __________ L. [Atomic mass Fe = 56, S = 32] Use molar volume 22.4L at 1 atm & 273 K.

Text Solution

Verified by Experts

The correct Answer is:
`15.4`
Molecular weight of `FeS_(2)` is 120g.
`4(120)gm to 11 mol O_(2)`
`6 gm FeS_(2)to` ?
Solving `(11)/(80)` mol of `O_(2)`
Volume of `O_(2)=((11)/(80)xx22.4)=3.08`
Volume of air `= ((100)/(20)xx3.08)=15.4L`
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