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The value of underset(r=0)overset(3)sum....

The value of `underset(r=0)overset(3)sum.^(8)C_(r)(.^(5)C_(r+1)-.^(4)C_(r))` is `"_____"`.

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The correct Answer is:
220

`""^(4)C_(r )+""^(4)C_(r +1)=""^(5)C_(r+1)`
`""^(4)C_(r+1)=""^(5)C_(r+1)-""^(4)C_(r )`
`sum_(r =0)^(3) ""^(8)C_(r )*""^(4)C_(r+1)=""^(8)C_(0)*""^(4)C_(1)+""^(8)C_(1)*""^(4)C_(2)+""^(8)C_(2)*""^(4)C_(3)+""^(8)C_(3)*""^(4)C_(4)`
`=""^(8)C_(8)*""^(4)C_(1)+""^(8)C_(7)*""^(4)C_(2)+""^(8)C_(6)*""^(4)C_(3)+""^(8)C_(5)*""^(4)C_(4)`
`""^(12)C_(9)=(12xx11xx10)/(6)=220`
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