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A ratio of contributions made by the ele...

A ratio of contributions made by the electric field and magnetic field components to the intensity of an EM wave is

A

`c: 1`

B

`c^(2): 1`

C

`1: 1`

D

`sqrtc : 1`

Text Solution

Verified by Experts

The correct Answer is:
C
`I_(E)` (intensity due to electric field) `= (1)/(2) c epsi_(0) E^(2)`,
`I_(B)` (intensity due to magnetic field) `= (cB^(2))/(2mu_(0))`
`(I_(E ))/(I_(B)) = ((1)/(2) c epsi_(0)E^(2))/(cB^(2)//2mu_(0))= (epsi_(0)mu_(0))(E//B)^(2) = ((1)/(c^(2)))(c^(2)) =1`
(as `c= (1)/(sqrt(epsi_(0)mu_(0)))and E//B=c`)
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