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A simple potentiometer circuit is shown ...

A simple potentiometer circuit is shown in the figure. The internal resistance of the battery is negligible. AB is a uniform wire of length 100cm and resistance `2Omega` What would be the length AC for zero galvanometer deflection (in mm)?

Text Solution

Verified by Experts

The correct Answer is:
825
`I = (4)/(2.4 + 2) = (4)/(4.4) = (1)/(1.1) = (10)/(11)`
If AC =x
Then `R_(AC) = (x)/(50) Omega `
`(10)/(11) xx (x)/(50)=1.5 implies " "x =1.5 xx 5 xx 11 = 82.5 cm`
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