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A circular current loop of magnetic mome...

A circular current loop of magnetic moment `M` is in an arbitrary orientation in an external magnetic field `vec(B)`. The work done to rotate the loop by `30^(@)` about an axis perpendicular to its plane is

A

`MB (1- (sqrt3)/(2))`

B

`sqrt3 (MB)/(2)`

C

`(MB)/(2)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A
`W_(ext)= Delta U + Delta K`
`W_("ext") = Delta U [Q Delta K=0]`
`=U_(2)-U_(1)`
`=- MB cos theta_(2) + MB cos theta_(1) = MB (cos theta_(1) - cos theta_(2))= MB (cos 0^(@) - cos 30^(@))`
`W_("ext") = MB (1- (sqrt3)/(2))`
`K_(i) =(1)/(2) m u^(2)`
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