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The efficiency of a heat engine is 1//6I...

The efficiency of a heat engine is `1//6`Its efficiency double when the temperature of sink decrease by `62^(@)C` its efficiency doubles.Then,What is the temperature of source?

A

`62^@C , 124 ^@C `

B

`99^@C ,37^@ C `

C

`124^@ C,62^@ C`

D

`37^@ C , 99^@ C `

Text Solution

Verified by Experts

The correct Answer is:
B
`eta=1 -(T_2)/( T_1)`
` 1/6 =1 - (T_2)/(T_1) implies (T_2)/(T_1) = 5/6`
Finally, efficiency is doubled on reducing sink temperature by `62^@ C.`
`implies (2)/(6) =1-(T_2 -62 )/(T_1) implies (T_2 -62 )/(T_1) = (4)/(6) implies (T_2 )/(T_1) - (62 )/(T_1) = (4 )/( 6 )`
` T_1 = 372 K = 99^@ C ," " T_2 = 310 K = 37^@ C `
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