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100g ice at 0^(@)C is mixed with 100g wa...

`100g` ice at `0^(@)C` is mixed with `100g` water at `100^(@)C`. The resultant temperature of the mixture is

Text Solution

Verified by Experts

The correct Answer is:
283
Let the final temperature of mixture be `theta `.
Then ` 100 xx 80 +100 ( theta -0) = 100 xx 1 xx ( 100 - theta)`
Solving, we get ` theta = 10^@ C = 283 K`
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