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If cell constant is 0.40 cm^(-1), the c...

If cell constant is `0.40 cm^(-1)`, the conductivity of 0.015 M NaCl solution having R = 1850 ohm is equal to

A

`1.08 xx 10^(-4) S cm^(-1)`

B

`4.32 xx 10^(-4)S cm^(-1)`

C

`2.16 xx 10^(-4) S cm^(-1)`

D

`5.04 xx 10^(-5) S cm^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
Conductivity (k) of an electrolytic conduction is given by
`k= ("Cell cons tant")/("Resistance") =(0.40)/(1850) S cm^(-1)=2.162 xx 10^(-4)S cm^(-1)`
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