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8.7 gm of pure MnO(2) is heated with a...

8.7 gm of pure `MnO_(2)` is heated with an excess of HCl and the gas evolved is passed into a solution of KI. The amount of `I_(2)` liberated is [Atomic mass O = 16, Mn = 55]

A

0.2 mole

B

25.4 gm

C

15.4 gm

D

7.7 gm

Text Solution

Verified by Experts

The correct Answer is:
B
`MnO_2 + 4HCl to MnCl_2 + Cl_2 + H_2 O`
`Cl_2 + 2Kl to I_2 + 2KCl`
Moles of `MnO_2 = (8.7)/(87) = 0.1`
Moles of `Cl_2 = 0.1`
Moles of `I_2= 0.1`
Mass of `I_2 = 0.1xx254 = 25.4` gm.
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