Home
Class 12
MATHS
The logical statement (p to q) vv (q to ...

The logical statement `(p to q) vv (q to ~ p)` is :

A

`~p`

B

`~q`

C

t (tautology)

D

F (fallacy)

Text Solution

AI Generated Solution

The correct Answer is:
To solve the logical statement `(p to q) vv (q to ~p)`, we will analyze it step by step using a truth table. ### Step 1: Identify the Variables We have two variables, \( p \) and \( q \). ### Step 2: Create the Truth Table Since there are two variables, the number of rows in the truth table will be \( 2^2 = 4 \). We will list all possible combinations of truth values for \( p \) and \( q \). | \( p \) | \( q \) | |---------|---------| | T | T | | T | F | | F | T | | F | F | ### Step 3: Calculate \( \neg p \) We will also need the negation of \( p \). | \( p \) | \( \neg p \) | |---------|--------------| | T | F | | T | F | | F | T | | F | T | ### Step 4: Calculate \( p \to q \) The implication \( p \to q \) is false only when \( p \) is true and \( q \) is false; otherwise, it is true. | \( p \) | \( q \) | \( p \to q \) | |---------|---------|----------------| | T | T | T | | T | F | F | | F | T | T | | F | F | T | ### Step 5: Calculate \( q \to \neg p \) The implication \( q \to \neg p \) is false only when \( q \) is true and \( \neg p \) is false; otherwise, it is true. | \( q \) | \( \neg p \) | \( q \to \neg p \) | |---------|--------------|---------------------| | T | F | F | | F | F | T | | T | T | T | | F | T | T | ### Step 6: Combine Results Now we will combine the results of \( p \to q \) and \( q \to \neg p \) using disjunction (logical OR). | \( p \) | \( q \) | \( p \to q \) | \( q \to \neg p \) | \( (p \to q) \vee (q \to \neg p) \) | |---------|---------|----------------|---------------------|-------------------------------------| | T | T | T | T | T | | T | F | F | T | T | | F | T | T | T | T | | F | F | T | T | T | ### Step 7: Conclusion Since the final column of the truth table is true for all possible combinations of \( p \) and \( q \), the logical statement `(p to q) vv (q to ~p)` is a tautology. ### Final Answer The logical statement `(p to q) vv (q to ~p)` is a tautology. ---

To solve the logical statement `(p to q) vv (q to ~p)`, we will analyze it step by step using a truth table. ### Step 1: Identify the Variables We have two variables, \( p \) and \( q \). ### Step 2: Create the Truth Table Since there are two variables, the number of rows in the truth table will be \( 2^2 = 4 \). We will list all possible combinations of truth values for \( p \) and \( q \). ...
Promotional Banner

Topper's Solved these Questions

  • MOCK TEST 12

    VMC MODULES ENGLISH|Exercise MATHEMATICS (SECTION 2)|5 Videos
  • MOCK TEST 11

    VMC MODULES ENGLISH|Exercise MATHEMATICS (Section-2)|5 Videos
  • MOCK TEST 13

    VMC MODULES ENGLISH|Exercise MATHEMATICS( SECTION-2)|5 Videos

Similar Questions

Explore conceptually related problems

Statements (p to q) harr (q to p)

The statement ~(p ^^ q) vv q

The logical statement (~ q implies ~p ) vv (~ q implies p) is equivalent to :

The following statement (p to q) to [(~p to q) to q] is

The statement p vv q is

If p and q are logical statements, then p rArr (~q rArr p) is equivalent to

The logical statement [~(~pvvq)vv(p^^r)]^^(~q^^r) is equivalent to (a) (~p^^~q)^^r (b) ~p vv r (c) (p^^r)^^~q (d) (p^^~q)vvr

The statement p Rightarrow p vv q

The compound statement (phArr q)vv(p hArr ~q) is logically equivalent to

Consider : Statement I: (p^^~q)^^(~p^^q) is a fallacy Statement II: (ptoq)harr(~q to ~p) is a tautology