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The solution set of the inequation |(1)/...

The solution set of the inequation `|(1)/(x)-2| lt 4`, is

A

`(-oo, -1//2)`

B

`(1//6, oo)`

C

`(-1//2, 1//6)`

D

`(-oo, -1//2) cup (1//6, oo)`

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To solve the inequation \(\left|\frac{1}{x} - 2\right| < 4\), we can break it down into two separate inequalities. Here’s the step-by-step solution: ### Step 1: Rewrite the Absolute Value Inequality The inequality \(\left|\frac{1}{x} - 2\right| < 4\) can be expressed as: \[ -4 < \frac{1}{x} - 2 < 4 \] ### Step 2: Split into Two Inequalities This gives us two inequalities to solve: 1. \(\frac{1}{x} - 2 < 4\) 2. \(\frac{1}{x} - 2 > -4\) ### Step 3: Solve the First Inequality For the first inequality: \[ \frac{1}{x} - 2 < 4 \] Adding 2 to both sides: \[ \frac{1}{x} < 6 \] Taking the reciprocal (and reversing the inequality since \(x\) must be positive): \[ x > \frac{1}{6} \] ### Step 4: Solve the Second Inequality For the second inequality: \[ \frac{1}{x} - 2 > -4 \] Adding 2 to both sides: \[ \frac{1}{x} > -2 \] Taking the reciprocal (and reversing the inequality since \(x\) must be positive): \[ x < -\frac{1}{2} \] ### Step 5: Combine the Results From the two inequalities, we have: 1. \(x > \frac{1}{6}\) 2. \(x < -\frac{1}{2}\) ### Step 6: Exclude the Point Where \(x = 0\) Since \(x\) cannot be zero (as it would make \(\frac{1}{x}\) undefined), we conclude that the solution set is: \[ x \in (-\infty, -\frac{1}{2}) \cup (\frac{1}{6}, \infty) \] ### Final Solution The solution set of the inequation \(\left|\frac{1}{x} - 2\right| < 4\) is: \[ (-\infty, -\frac{1}{2}) \cup (\frac{1}{6}, \infty) \]

To solve the inequation \(\left|\frac{1}{x} - 2\right| < 4\), we can break it down into two separate inequalities. Here’s the step-by-step solution: ### Step 1: Rewrite the Absolute Value Inequality The inequality \(\left|\frac{1}{x} - 2\right| < 4\) can be expressed as: \[ -4 < \frac{1}{x} - 2 < 4 \] ...
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OBJECTIVE RD SHARMA ENGLISH-ALGEBRAIC INEQUATIONS-Section I - Solved Mcqs
  1. The solution set of the inequation (x-1)/(x-2) gt 2, is

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  2. The complete set of values of 'x' which satisfy the inequations: 5x+2...

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  3. The solution set of the inequation |2x-3| lt x-1, is

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  4. Write the solution set of the inequation |x-1|geq|x-3|dot

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  5. The solution set of the inequation |x|-1 lt 1-x, is

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  6. The set of all real numbers x for which x^2-|x+2|+x >0 is (-oo,-2) b. ...

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  7. The solution set of the inequation (|x+3|+x)/(x+2) gt 1, is

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  8. The set of values of x for which the inequality |x-1|+|x+1|lt 4 always...

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  9. The solution set of the inequation |[|x|-7]|-5< 0, is ... ([*] denote...

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  10. If [x] denotes the greatest integer less than or equal to x, then the ...

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  11. The area of the region represented by |x-y| le 3 " and " |x+y|le 3, is

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  12. The total number of integral points i.e. points having integral coordi...

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  13. The solution set of the inequation |(1)/(x)-2| lt 4, is

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  14. The set of real values of x satisfying the inequality |x^(2) + x -6| l...

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  15. The set of real values of x satisfying ||x-1|-1|le 1, is

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  16. The largest interval for whichx^(12)+x^9+x^4-x+1>0 -4<xlt=0 b. 0<x<1 ...

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  17. The number of integral solutions of x^2+9<(x+3)^2<8x+25 is

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  18. If x^2-ax+1-2a^2 > 0 for all x in R, then ....

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  19. The least integral value of 'k' for which (k -2)x^2 +8x+k+4>0 for all ...

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  20. If 9^(x+1) + (a^(2)-4a-2) 3^(x) + 1 lt 0 "for all" x in R, then

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