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The number of integral solutions of x^(2...

The number of integral solutions of `x^(2)-3x-4 lt 0`, is

A

3

B

4

C

6

D

none of these

Text Solution

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The correct Answer is:
To find the number of integral solutions for the inequality \( x^2 - 3x - 4 < 0 \), we will follow these steps: ### Step 1: Rewrite the Inequality We start with the inequality: \[ x^2 - 3x - 4 < 0 \] ### Step 2: Factor the Quadratic Expression Next, we need to factor the quadratic expression \( x^2 - 3x - 4 \). We can do this by looking for two numbers that multiply to \(-4\) (the constant term) and add to \(-3\) (the coefficient of \(x\)). The numbers \(-4\) and \(1\) satisfy these conditions. Thus, we can factor the expression as: \[ (x - 4)(x + 1) < 0 \] ### Step 3: Identify Critical Points The critical points occur where the expression equals zero. Setting each factor to zero gives us: \[ x - 4 = 0 \quad \Rightarrow \quad x = 4 \] \[ x + 1 = 0 \quad \Rightarrow \quad x = -1 \] Thus, the critical points are \(x = -1\) and \(x = 4\). ### Step 4: Test Intervals We will test the sign of the product \( (x - 4)(x + 1) \) in the intervals determined by the critical points: 1. **Interval \( (-\infty, -1) \)**: Choose \( x = -2 \): \[ (-2 - 4)(-2 + 1) = (-6)(-1) = 6 \quad (\text{positive}) \] 2. **Interval \( (-1, 4) \)**: Choose \( x = 0 \): \[ (0 - 4)(0 + 1) = (-4)(1) = -4 \quad (\text{negative}) \] 3. **Interval \( (4, \infty) \)**: Choose \( x = 5 \): \[ (5 - 4)(5 + 1) = (1)(6) = 6 \quad (\text{positive}) \] ### Step 5: Determine the Solution Set From our tests, we find: - The expression is positive in the intervals \( (-\infty, -1) \) and \( (4, \infty) \). - The expression is negative in the interval \( (-1, 4) \). Since we are looking for where the expression is less than zero, the solution set is: \[ -1 < x < 4 \] ### Step 6: Identify Integral Solutions Now, we need to find the integral solutions within the interval \( (-1, 4) \). The integers that satisfy this inequality are: \[ 0, 1, 2, 3 \] ### Step 7: Count the Integral Solutions The integral solutions are \(0, 1, 2, 3\), which gives us a total of: \[ \text{Number of integral solutions} = 4 \] Thus, the final answer is: \[ \boxed{4} \]
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