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If e^(x)=y+sqrt(1+y^(2) then the value o...

If `e^(x)=y+sqrt(1+y^(2)` then the value of y is

A

`e^(x)-e^(-x)`

B

`1/2(e^(x)-e^(-x))`

C

`e^(x)+e^(-x)`

D

`1/2(e^(x)+e^(-x))`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \( e^x = y + \sqrt{1 + y^2} \) for \( y \), we can follow these steps: ### Step 1: Rearrange the equation We start with the given equation: \[ e^x = y + \sqrt{1 + y^2} \] We can rearrange this to isolate the square root: \[ \sqrt{1 + y^2} = e^x - y \] ### Step 2: Square both sides Next, we square both sides to eliminate the square root: \[ 1 + y^2 = (e^x - y)^2 \] Expanding the right side, we get: \[ 1 + y^2 = e^{2x} - 2e^x y + y^2 \] ### Step 3: Simplify the equation Now, we can simplify the equation by subtracting \( y^2 \) from both sides: \[ 1 = e^{2x} - 2e^x y \] ### Step 4: Rearrange to solve for \( y \) Next, we rearrange the equation to isolate the term involving \( y \): \[ 2e^x y = e^{2x} - 1 \] Now, divide both sides by \( 2e^x \): \[ y = \frac{e^{2x} - 1}{2e^x} \] ### Step 5: Further simplify We can simplify this expression: \[ y = \frac{1}{2} \left( \frac{e^{2x}}{e^x} - \frac{1}{e^x} \right) \] This simplifies to: \[ y = \frac{1}{2} \left( e^x - e^{-x} \right) \] ### Final Answer Thus, the value of \( y \) is: \[ y = \frac{1}{2} (e^x - e^{-x}) \] ---
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OBJECTIVE RD SHARMA ENGLISH-EXPONENTIAL AND LOGARITHMIC SERIES-Exercise
  1. The sum of the series (1^(2).2^(2))/(1!)+(2^(2).3^(2))/(2!)+(3^(2).4^(...

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  2. The value of (x+y)(x-y)+1/(2!)(x+y)(x-y)(x^2+y^2)+1/(3!)(x+y)(x-y)(x^4...

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  3. If e^(x)=y+sqrt(1+y^(2) then the value of y is

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  4. If (e^(5x)+e^(x))/(e^(3x)) is expand in a series of ascending powers o...

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  5. In the expansion of (e^(7x)+e^(3x))/(e^(5x)) the constant term is

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  6. The value of sqrt(2-1)/sqrt(2)+3-2sqrt(2)/(4)+(5sqrt2-7/6)sqrt(2)+17-1...

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  7. If y=2x^(2)-1 then (1)/(x^(2))+(1)/(2x^(4))+(1)/(3x^(6))+…infty equals...

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  8. The sum of sum(n=1)^(oo) ""^(n)C(2) . (3^(n-2))/(n!) equal

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  9. If (e^(x))/(1-x) = B(0) +B(1)x+B(2)x^(2)+...+B(n)x^(n)+... , then the ...

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  10. IfS=Sigma(n=1)^(oo) (""^(n)C(0)+""^(n)C(1)+""^(n)c(2)+..+""^(n)C(n))/(...

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  11. If S=sum(n=2)^(oo) (3n^2+1)/((n^2-1)^3) then 9/4Sequals

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  12. 1/(1.2)+(1.3)/(1.2.3.4)+(1.3.5)/(1.2.3.4.5.6)+.....oo

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  13. The sum of the series (12)/(2!)+(28)/(3!)+(50)/(4!)+(78)/(5!)+…is

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  14. If a=Sigma(n=0)^(oo) (x^(3x))/(3n)!,b=Sigma(n=1)^(oo)(x^(3n-2))/(3n-2!...

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  15. If S(n) denotes the sum of the products of the products of the first n...

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  16. sum(n=0)^oo (loge x)^n/(n!) is equal to

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  17. If a = Sigma(n=1)^(oo) (2n)/(2n-1!),b=Sigma(n=1)^(oo) (2n)/(2n+1!) the...

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  18. The value of (1+(a^(2)x^(2))/(2!)+(a^(4)x^(4))/(4!)+…)^(2)-(ax+(a^(3...

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  19. If S(n)=(1^(2).(2))/(1!)+(2^(2).3)/(2!)+(3^(2).4)/(3!)+…(n^(2).(n+1))...

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  20. If S=Sigma(n=0)^(oo) (logx)^(2n)/(2n!) , then S equals

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