A code ward of length 4 consists two distinct consonant in the English alphabet followed by two digits from 1 to 9 with repetition allowed in digits. If the number of code wards so formed ending with an even digit is 432`xx`k, then k is equal to

Options

A. 7
B. 5
C. 49
D. 35

Explanation

To solve the problem, we need to determine the value of \( k \) in the expression \( 432 \times k \) that equals the total number of code words formed. Let's break down the solution step by step.

### Step 1: Identify the components of the code word
The code word consists of:
- Two distinct consonants
- Two digits from 1 to 9, with repetition allowed in digits

### Step 2: Count the consonants
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