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Five persons entered the lift cabin on the ground floor of an 8-floor house. Suppose each of them can leave the cabin independently at any floor beginning with the first. Find the total number of ways in which each of the five persons can leave the cabin (i) at any one of the 7 floors (ii) at different floors.

A

`5^(7)`

B

2520

C

`7^(5)`

D

35

Text Solution

Verified by Experts

Suppose `A_(1),A_(2),A_(3),A_(4),A_(5)` are five persons. `A_(1)` can leave the cabin at any of the seven floors. So, `A_(1)` can leave the cabin in 7 ways. Similarly, each of `A_(2),A_(3),A_(4),A_(5)` can leave the cabin in 7 ways. Thus the total number of ways in which each of the five persons can leave the cabin at any of the seven floors is `7xx7xx7xx7xx7=7^(5)`.
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OBJECTIVE RD SHARMA ENGLISH-PERMUTATIONS AND COMBINATIONS-Chapter Test
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