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In how many ways five different rings ca...

In how many ways five different rings can be worn in four fingers with at least one ring in each finger?

A

120

B

96

C

20

D

480

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AI Generated Solution

The correct Answer is:
To solve the problem of how many ways five different rings can be worn on four fingers with at least one ring on each finger, we can follow these steps: ### Step 1: Choose Rings for Fingers Since we have four fingers and we need to place at least one ring on each finger, we first need to choose 4 rings out of the 5 available rings. The number of ways to choose 4 rings from 5 is given by the combination formula: \[ \binom{n}{r} = \frac{n!}{r!(n-r)!} \] where \( n \) is the total number of items to choose from, and \( r \) is the number of items to choose. In this case: \[ \binom{5}{4} = \frac{5!}{4! \cdot (5-4)!} = \frac{5!}{4! \cdot 1!} = 5 \] ### Step 2: Arrange the Chosen Rings Once we have chosen 4 rings, we need to arrange these 4 rings on the 4 fingers. The number of ways to arrange 4 rings is given by the factorial of the number of rings: \[ 4! = 4 \times 3 \times 2 \times 1 = 24 \] ### Step 3: Place the Remaining Ring Now, we have 1 ring left (since we started with 5 rings and used 4). This remaining ring can be placed on any of the 4 fingers. Therefore, there are 4 options for placing this remaining ring. ### Step 4: Calculate the Total Number of Ways Now, we can calculate the total number of ways to wear the rings by multiplying the number of ways to choose the rings, the number of ways to arrange them, and the number of options for the remaining ring: \[ \text{Total Ways} = \binom{5}{4} \times 4! \times 4 \] Substituting the values we calculated: \[ \text{Total Ways} = 5 \times 24 \times 4 \] Calculating this gives: \[ 5 \times 24 = 120 \] \[ 120 \times 4 = 480 \] ### Final Answer Thus, the total number of ways to wear the five different rings on four fingers with at least one ring on each finger is **480**. ---

To solve the problem of how many ways five different rings can be worn on four fingers with at least one ring on each finger, we can follow these steps: ### Step 1: Choose Rings for Fingers Since we have four fingers and we need to place at least one ring on each finger, we first need to choose 4 rings out of the 5 available rings. The number of ways to choose 4 rings from 5 is given by the combination formula: \[ \binom{n}{r} = \frac{n!}{r!(n-r)!} ...
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OBJECTIVE RD SHARMA ENGLISH-PERMUTATIONS AND COMBINATIONS-Chapter Test
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  2. 7 women and 7 men are to sit round a circulartable such that there is ...

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  3. There are (n+1) white and (n+1) black balls, each set numbered 1ton...

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  4. 12 persons are to be arranged to a round table. If two particular pers...

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  5. The number of committees of 5 persons consisting of at least one femal...

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  6. The number of ways in which a team of eleven players can be selected f...

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  7. In a football championship, 153 matches were played. Every two-team pl...

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  8. How many numbers between 5000 and 10,000 can be formed using the digit...

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  9. If x, y and r are positive integers, then ""^(x)C(r)+""^(x)C(r-1)+""^(...

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  10. In how many ways can 5 red and 4 white balls be drawn from a bag conta...

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  11. All the letters of the word 'EAMCET' are arranged in all possible ways...

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  12. There are 10 lamps in a hall. Each one of them can be switched on i...

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  13. How many 10-digit numbers can be formed by using digits 1 and 2

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  14. The straight lines I(1),I(2),I(3) are parallel and lie in the same pla...

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  15. about to only mathematics

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  16. The number of diagonals that can be drawn by joining the vertices of a...

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  17. The sum of the digits in unit place of all the numbers formed with the...

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  18. In an examinations there are three multiple choice questions and each ...

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  19. There are 10 points in a plane, out of these 6 are collinear. If N is ...

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  20. Ramesh has 6 friends. In how many ways can be invite one or more of th...

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  21. If Pm stands for ^m Pm , then prove that: 1+1. P1+2. P2+3. P3++ndotPn=...

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