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If the letters of the word SACHIN are ar...

If the letters of the word SACHIN are arranged in all possible ways and these words are written out as in dictionary, then the word SACHIN appears at serial number 602 (2) 603 (3) 600 (4) 601

A

602

B

603

C

600

D

601

Text Solution

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each question can be answered in two ways. So, total number of ways of answering 10 questions is
`2xx2xx2xx....xx2` (10 times) `=2^(10)=1024`
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OBJECTIVE RD SHARMA ENGLISH-PERMUTATIONS AND COMBINATIONS-Chapter Test
  1. If the letters of the word SACHIN are arranged in all possible ways...

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  2. 7 women and 7 men are to sit round a circulartable such that there is ...

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  3. There are (n+1) white and (n+1) black balls, each set numbered 1ton...

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  4. 12 persons are to be arranged to a round table. If two particular pers...

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  5. The number of committees of 5 persons consisting of at least one femal...

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  6. The number of ways in which a team of eleven players can be selected f...

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  7. In a football championship, 153 matches were played. Every two-team pl...

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  8. How many numbers between 5000 and 10,000 can be formed using the digit...

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  9. If x, y and r are positive integers, then ""^(x)C(r)+""^(x)C(r-1)+""^(...

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  10. In how many ways can 5 red and 4 white balls be drawn from a bag conta...

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  11. All the letters of the word 'EAMCET' are arranged in all possible ways...

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  12. There are 10 lamps in a hall. Each one of them can be switched on i...

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  13. How many 10-digit numbers can be formed by using digits 1 and 2

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  14. The straight lines I(1),I(2),I(3) are parallel and lie in the same pla...

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  15. about to only mathematics

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  16. The number of diagonals that can be drawn by joining the vertices of a...

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  17. The sum of the digits in unit place of all the numbers formed with the...

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  18. In an examinations there are three multiple choice questions and each ...

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  19. There are 10 points in a plane, out of these 6 are collinear. If N is ...

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  20. Ramesh has 6 friends. In how many ways can be invite one or more of th...

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  21. If Pm stands for ^m Pm , then prove that: 1+1. P1+2. P2+3. P3++ndotPn=...

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