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A = { x // x in R, x != 0, -4 <= x <= 4...

`A = { x // x in R, x != 0, -4 <= x <= 4` and `f: A -> R` is defined by `f(x) = |x| / x` for `x in A`. Then the range of f is

A

{1,-1}

B

`{x:0 le x le 4}`

C

{1}

D

`{x: -4 le x le 0}`

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The correct Answer is:
To find the range of the function \( f: A \to \mathbb{R} \) defined by \( f(x) = \frac{|x|}{x} \) for \( x \in A \), where \( A = \{ x \in \mathbb{R} \mid x \neq 0, -4 \leq x \leq 4 \} \), we can follow these steps: ### Step 1: Identify the domain The set \( A \) consists of all real numbers \( x \) such that \( -4 \leq x \leq 4 \) and \( x \neq 0 \). Therefore, we can express \( A \) as: \[ A = [-4, 0) \cup (0, 4] \] ### Step 2: Analyze the function \( f(x) \) The function \( f(x) = \frac{|x|}{x} \) can be analyzed based on the sign of \( x \): - If \( x > 0 \), then \( |x| = x \), so: \[ f(x) = \frac{x}{x} = 1 \] - If \( x < 0 \), then \( |x| = -x \), so: \[ f(x) = \frac{-x}{x} = -1 \] ### Step 3: Determine the output values for the intervals in \( A \) - For \( x \in (0, 4] \) (positive values), \( f(x) = 1 \). - For \( x \in [-4, 0) \) (negative values), \( f(x) = -1 \). ### Step 4: Conclusion about the range Since \( f(x) \) takes the value \( 1 \) for all positive \( x \) in \( (0, 4] \) and the value \( -1 \) for all negative \( x \) in \( [-4, 0) \), the range of \( f \) is: \[ \text{Range of } f = \{-1, 1\} \] ### Final Answer The range of the function \( f \) is \( \{-1, 1\} \). ---
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  10. The function f:R to R given by f(x)=x^(2)+x is

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  11. Let f:R to R and g:R to R be given by f(x)=3x^(2)+2 and g(x)=3x-1 for ...

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  12. The function of f:R to R, defined by f(x)=[x], where [x] denotes the g...

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  13. Let f(x)=x,g(x)=1/x and h(x)=f(x)g(x) . Then h(x)=1 for a.x in R b. x...

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  14. If the functions of f and g are defined by f(x)=3x-4 and g(x)=2+3x the...

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  16. The function f:R to R is defined by f(x)=cos^(2)x+sin^(4)x for x in R....

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  17. A = { x // x in R, x != 0, -4 <= x <= 4 and f: A -> R is defined by f...

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  18. If f: RvecR and g: RvecR are defined by f(x)=2x+3a n dg(x)=x^2+7, then...

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  19. Let f(x) be defined on [-2,2] and be given by f(x)={(-1",",-2 le x l...

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