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The term independent of x in the expansi...

The term independent of x in the expansion of `((1)/(x^(2)) + (1)/(x) +1 + x + x^(2))^(5)`, is

A

381

B

441

C

439

D

359

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AI Generated Solution

The correct Answer is:
To find the term independent of \( x \) in the expansion of \[ \left( \frac{1}{x^2} + \frac{1}{x} + 1 + x + x^2 \right)^5, \] we can follow these steps: ### Step 1: Rewrite the expression We start by rewriting the expression in a more manageable form: \[ \left( \frac{1}{x^2} + \frac{1}{x} + 1 + x + x^2 \right)^5. \] ### Step 2: Identify the powers of \( x \) We can express each term in the expansion in terms of powers of \( x \): - \( \frac{1}{x^2} \) corresponds to \( x^{-2} \) - \( \frac{1}{x} \) corresponds to \( x^{-1} \) - \( 1 \) corresponds to \( x^0 \) - \( x \) corresponds to \( x^1 \) - \( x^2 \) corresponds to \( x^2 \) ### Step 3: Use the multinomial theorem We can use the multinomial theorem to expand the expression. The general term in the expansion will be of the form: \[ \frac{5!}{a_1! a_2! a_3! a_4! a_5!} \left( \frac{1}{x^2} \right)^{a_1} \left( \frac{1}{x} \right)^{a_2} (1)^{a_3} (x)^{a_4} (x^2)^{a_5}, \] where \( a_1 + a_2 + a_3 + a_4 + a_5 = 5 \). ### Step 4: Find the exponent of \( x \) The exponent of \( x \) in the general term is given by: \[ -2a_1 - a_2 + a_4 + 2a_5. \] We want to find the values of \( a_1, a_2, a_3, a_4, a_5 \) such that the exponent of \( x \) is zero: \[ -2a_1 - a_2 + a_4 + 2a_5 = 0. \] ### Step 5: Solve for combinations We also have the constraint: \[ a_1 + a_2 + a_3 + a_4 + a_5 = 5. \] We can express \( a_3 \) in terms of the other variables: \[ a_3 = 5 - (a_1 + a_2 + a_4 + a_5). \] ### Step 6: Substitute and simplify Now, we can substitute \( a_3 \) back into the equation and solve for different combinations of \( a_1, a_2, a_4, a_5 \) that satisfy both equations. ### Step 7: Calculate the coefficient Once we find the valid combinations of \( a_1, a_2, a_4, a_5 \), we can calculate the coefficient of the term using the multinomial coefficient. ### Step 8: Find the independent term Finally, we sum the coefficients of all the terms that are independent of \( x \).

To find the term independent of \( x \) in the expansion of \[ \left( \frac{1}{x^2} + \frac{1}{x} + 1 + x + x^2 \right)^5, \] we can follow these steps: ...
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OBJECTIVE RD SHARMA ENGLISH-BINOMIAL THEOREM AND ITS APPLCIATIONS -Section I - Solved Mcqs
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  3. Let f(n)= sum(k=1)^(n) k^2 ^"(n )Ck)^ 2 then the value of f(5) equals

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  4. If C(0), C(1), C(2), …, C(n) denote the binomial coefficients in th...

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  5. If for n in N ,sum(k=0)^(2n)(-1)^k(^(2n)Ck)^2=A , then find the value...

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  7. If C(0), C(1) C(2) ….., denote the binomial coefficients in the exp...

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  8. If C0, C1,C2 ..., Cn, denote the binomial coefficients in the expans...

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  9. For r = 0, 1,"…..",10, let A(r),B(r), and C(r) denote, respectively, t...

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