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The coefficient of x^(8) y^(6) z^(4) in ...

The coefficient of `x^(8) y^(6) z^(4)` in the expansion of `(x + y + z)^(18)`, is not equal to

A

`""^(18)C_(14) xx""^(14)C_(8)`

B

`""^(18)C_(10)xx""^(10)C_(6)`

C

`""^(18)C_(6) xx""^(12)C_(8)`

D

`""^(18)C_(6)xx""^(14)C_(6)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the coefficient of \( x^8 y^6 z^4 \) in the expansion of \( (x + y + z)^{18} \), we can use the multinomial theorem. The coefficient can be calculated using the formula: \[ \text{Coefficient} = \frac{n!}{p! \, q! \, r!} \cdot a^p \cdot b^q \cdot c^r \] where \( n \) is the total power (18 in this case), \( p \), \( q \), and \( r \) are the powers of \( x \), \( y \), and \( z \) respectively, and \( a \), \( b \), and \( c \) are the coefficients of \( x \), \( y \), and \( z \) (which are all 1 here). ### Step 1: Identify the values - \( n = 18 \) - \( p = 8 \) (power of \( x \)) - \( q = 6 \) (power of \( y \)) - \( r = 4 \) (power of \( z \)) ### Step 2: Apply the formula Substituting the values into the formula gives: \[ \text{Coefficient} = \frac{18!}{8! \, 6! \, 4!} \] ### Step 3: Calculate the coefficient Now we can compute the value of the coefficient: 1. Calculate \( 18! \) 2. Calculate \( 8! \), \( 6! \), and \( 4! \) 3. Substitute these values into the equation. ### Step 4: Check the options We need to check which of the given options is not equal to \( \frac{18!}{8! \, 6! \, 4!} \). #### Option A: \( 18C14 \) \[ 18C14 = \frac{18!}{14! \, 4!} = \frac{18!}{(18-4)! \, 4!} \] This can be rewritten as: \[ = \frac{18!}{14! \, 4!} = \frac{18!}{8! \, 6! \, 4!} \] This is equal to our coefficient. #### Option B: \( 18C18 \) \[ 18C18 = \frac{18!}{18! \, 0!} = 1 \] This is not equal to our coefficient. #### Option C: \( 18C16 \) \[ 18C16 = \frac{18!}{16! \, 2!} = \frac{18!}{(18-2)! \, 2!} \] This can be rewritten as: \[ = \frac{18!}{16! \, 2!} = \frac{18!}{6! \, 4! \, 8!} \] This is equal to our coefficient. #### Option D: \( 18C12 \) \[ 18C12 = \frac{18!}{12! \, 6!} = \frac{18!}{(18-6)! \, 6!} \] This can be rewritten as: \[ = \frac{18!}{12! \, 6!} = \frac{18!}{8! \, 4! \, 6!} \] This is equal to our coefficient. ### Conclusion The only option that is not equal to the coefficient \( \frac{18!}{8! \, 6! \, 4!} \) is **Option B**.
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OBJECTIVE RD SHARMA ENGLISH-BINOMIAL THEOREM AND ITS APPLCIATIONS -Exercise
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  10. about to only mathematics

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  15. Let (1+x)^(n)=sum(r=0)^(n)a(r)x^(r)* Then (1+(a(1))/(a(0)))(1+(a(2))/(...

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  18. If (1+2x+3x^2)^(10)=a0+a1x+a2x^2++a(20)x^(20),t h e na1 equals 10 b. 2...

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