Show that the area of the parallelogram formed by the lines `2x-3y+a=0,\ 3x-2y-a=0,\ 2x-3y+3a=0\ a n d\ 3x-2y-2a=0\ is(2a^2)/5s qdotu n i t sdot`

Options

A. `(a^(2))/(5)`
B. `(2a^(2))/(5)`
C. `(3a^(2))/(5)`
D. none of these

Answer

B

Explanation

Let A be the required area. Then, A=`|((3a-a){-2a-(-a)})/(|{:(2,-3),(3,-2):}|)|=(2a^(2))/(5)` sq. units.