If one of the lines of `m y^2+(1-m^2)x y-m x^2=0` is a bisector of the angle between the lines `x y=0` , then `m` is 1 (b) 2 (c) `-1/2` (d) `-1`

Options

A. 1
B. 2
C. `-1//2`
D. `-2`

Answer

A

Explanation

Clearly, lines given by xy = 0 are x = 0, y = 0 i.e. the coordinate axes and their bisectors are `y = pm x.`
Putting `y=pm x` in `my^(2)+(1-m^(2))xy-mx^(2)=0`, we get
`1-m^(2)=0 rArr m = pm 1`
Hence, option (a) is correct.