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The lines represented by x^(2)+2lambda x...

The lines represented by `x^(2)+2lambda xy+2y^(2)=0` and the lines represented by `1+lambda_x^(2)-8xy+y^(2)=0` are equally inclined, then

A

`lambda` is any real number

B

`lambda gt 2`

C

`lambda = pm2`

D

`lambda lt -2`

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The correct Answer is:
To solve the problem, we need to analyze the given equations of the lines and determine the conditions under which they are equally inclined. ### Step-by-Step Solution: 1. **Identify the equations of the lines:** The first equation is: \[ x^2 + 2\lambda xy + 2y^2 = 0 \] The second equation is: \[ 1 + \lambda x^2 - 8xy + y^2 = 0 \] 2. **Rewrite the first equation:** The first equation can be rewritten in the form of a quadratic in \(x\) and \(y\): \[ x^2 + 2\lambda xy + 2y^2 = 0 \] This represents two lines which can be expressed as: \[ m_1, m_2 = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] where \(a = 1\), \(b = 2\lambda\), and \(c = 2\). 3. **Calculate the slopes of the lines:** The slopes of the lines represented by the first equation are given by: \[ m_1, m_2 = \frac{-2\lambda \pm \sqrt{(2\lambda)^2 - 4 \cdot 1 \cdot 2}}{2 \cdot 1} \] Simplifying this gives: \[ m_1, m_2 = \frac{-2\lambda \pm \sqrt{4\lambda^2 - 8}}{2} \] \[ = -\lambda \pm \sqrt{\lambda^2 - 2} \] 4. **Rewrite the second equation:** The second equation can be rearranged as: \[ \lambda x^2 - 8xy + (y^2 + 1) = 0 \] This also represents two lines. 5. **Calculate the slopes of the lines from the second equation:** The slopes of the lines represented by the second equation are given by: \[ m_3, m_4 = \frac{8 \pm \sqrt{(-8)^2 - 4\lambda(1)}}{2\lambda} \] \[ = \frac{8 \pm \sqrt{64 - 4\lambda}}{2\lambda} \] 6. **Condition for equally inclined lines:** For the lines to be equally inclined, the product of the slopes must equal -1: \[ (m_1 - m_2)(m_3 - m_4) = -1 \] 7. **Set up the equations:** From the slopes calculated, we can set up the equations: \[ (-\lambda + \sqrt{\lambda^2 - 2}) - (-\lambda - \sqrt{\lambda^2 - 2}) = 2\sqrt{\lambda^2 - 2} \] and \[ (8 + \sqrt{64 - 4\lambda}) - (8 - \sqrt{64 - 4\lambda}) = 2\sqrt{64 - 4\lambda} \] 8. **Equate and solve for \(\lambda\):** Setting up the equation: \[ 2\sqrt{\lambda^2 - 2} \cdot 2\sqrt{64 - 4\lambda} = -1 \] Simplifying this will lead to a quadratic equation in \(\lambda\). 9. **Final result:** Solving the quadratic equation will yield the values of \(\lambda\) that satisfy the condition of equal inclination.

To solve the problem, we need to analyze the given equations of the lines and determine the conditions under which they are equally inclined. ### Step-by-Step Solution: 1. **Identify the equations of the lines:** The first equation is: \[ x^2 + 2\lambda xy + 2y^2 = 0 ...
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OBJECTIVE RD SHARMA ENGLISH-PAIR OF STRAIGHT LINES-Section I - Solved Mcqs
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