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If the equation 2x^(2)+2hxy +6y^(2) - 4x...

If the equation `2x^(2)+2hxy +6y^(2) - 4x +5y -6 = 0` represents a pair of straight lines, then the length of intercept on the x-axis cut by the lines is equal to

A

2

B

4

C

`sqrt7`

D

0

Text Solution

Verified by Experts

The correct Answer is:
B

The x-coordinates of the points of intersection of the pair of lines by `2x^(2)+2hxy+6y^(2)-4x+5y-6=0` and x-axis are roots of the equation
`2x^(2)-4x-6=0`
or, `x^(2)-2x-3=0`
`rArr" "(x-3)(x+1)=0 rArr x=-1, 3`
Hence, required length `=|x_(1)-x_(2)|=4.`
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