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The difference of the tangents of the an...

The difference of the tangents of the angles which the lines `x^(2)(sec^(2)-sin^(2)theta)-2xy tan theta +y^(2)sin^(2) theta=0` make with X-axis, is

A

`2 tan theta`

B

2

C

`2 cot theta`

D

`sin 2 theta`

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The correct Answer is:
To solve the problem of finding the difference of the tangents of the angles which the lines represented by the equation \[ x^2 \sec^2 \theta - \sin^2 \theta - 2xy \tan \theta + y^2 \sin^2 \theta = 0 \] make with the X-axis, we will follow these steps: ### Step 1: Identify the coefficients We start by rewriting the given equation in the standard form of a pair of straight lines: \[ Ax^2 + 2Hxy + By^2 = 0 \] From the given equation, we can identify: - \( A = \sec^2 \theta \) - \( B = \sin^2 \theta \) - \( 2H = -2 \tan \theta \) which gives \( H = -\tan \theta \) ### Step 2: Use the formulas for slopes For the pair of lines, the slopes \( m_1 \) and \( m_2 \) can be calculated using the formulas: - \( m_1 + m_2 = -\frac{2H}{B} \) - \( m_1 m_2 = \frac{A}{B} \) Substituting the values we identified: 1. \( m_1 + m_2 = -\frac{2(-\tan \theta)}{\sin^2 \theta} = \frac{2\tan \theta}{\sin^2 \theta} = 2 \frac{\tan \theta}{\sin^2 \theta} \) 2. \( m_1 m_2 = \frac{\sec^2 \theta}{\sin^2 \theta} \) ### Step 3: Find the difference of the slopes To find the difference of the slopes \( m_1 - m_2 \), we use the identity: \[ (m_1 - m_2)^2 = (m_1 + m_2)^2 - 4m_1 m_2 \] Substituting the values: \[ (m_1 - m_2)^2 = \left(2 \frac{\tan \theta}{\sin^2 \theta}\right)^2 - 4 \left(\frac{\sec^2 \theta}{\sin^2 \theta}\right) \] ### Step 4: Simplify the expression Calculating \( (m_1 - m_2)^2 \): 1. \( (m_1 + m_2)^2 = 4 \frac{\tan^2 \theta}{\sin^4 \theta} \) 2. \( 4m_1 m_2 = 4 \cdot \frac{\sec^2 \theta}{\sin^2 \theta} = 4 \cdot \frac{1}{\cos^2 \theta \sin^2 \theta} \) Thus, \[ (m_1 - m_2)^2 = 4 \frac{\tan^2 \theta}{\sin^4 \theta} - 4 \cdot \frac{1}{\cos^2 \theta \sin^2 \theta} \] ### Step 5: Factor out the common terms Factoring out \( 4 \): \[ (m_1 - m_2)^2 = 4 \left( \frac{\tan^2 \theta}{\sin^4 \theta} - \frac{1}{\cos^2 \theta \sin^2 \theta} \right) \] ### Step 6: Find the difference of the tangents To find \( m_1 - m_2 \): \[ m_1 - m_2 = \sqrt{4} = 2 \] Thus, the difference of the tangents of the angles which the lines make with the X-axis is \( 2 \). ### Final Answer The difference of the tangents of the angles which the lines make with the X-axis is \( \boxed{2} \).
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OBJECTIVE RD SHARMA ENGLISH-PAIR OF STRAIGHT LINES-Exercise
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  6. The equation y^(2)-x^(2)+2x-1=0, represents

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  7. The angle between the straight lines x^(2)-y^(2)-2x-1=0, is

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  8. If the angle between the two lines represented by 2x^2+5x y+3y^2+6x+7y...

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  9. The diagonal of the rectangle formed by the lines x^2-7x +6= 0 and y^2...

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  10. The angle between the pair of straight lines 2x^2+5xy+2y^2+3x+3y+1=0 i...

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  11. The circumcentre of the triangle formed by the lines, xy + 2x + 2y + 4...

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  12. Distance between the lines represented by 9x^2-6x y+y^2+18 x-6y+8=0 , ...

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  13. The joint equation of the straight lines x+y=1 and x-y=4, is

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  16. If x^(2)-kxy+y^(2)+2y+2=0 denotes a pair of straight lines then k =

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  17. The equations of a line which is parallel to the line common to the p...

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  18. If the slope of one of the lines given by 36x^(2)+2hxy+72y^(2)=0 is fo...

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  19. The combined equation of the pair of the straight lines through the po...

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  20. The equation x^(3)-6x^(2)y+11xy^(2)-6y^(3)=0 represents three straight...

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