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The age distribution of 400 persons in ...

The age distribution of 400 persons in a colony having median age 32 is given below:
`{:("Age (in years) :", 20-25,25-30,30-35,35-40,40-45,45-50),("Frequency :", 110,x,75,55,y,30):}`
Then, x - y is

A

10

B

20

C

-10

D

-20

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the values of \( x \) and \( y \) from the given age distribution and then calculate \( x - y \). ### Step 1: Identify the Median Class The median age is given as 32, which lies in the age group 30-35. Therefore, the median class is 30-35. ### Step 2: Write Down the Given Frequencies The frequency distribution is as follows: - Age (in years): 20-25, 25-30, 30-35, 35-40, 40-45, 45-50 - Frequency: 110, \( x \), 75, 55, \( y \), 30 ### Step 3: Calculate Cumulative Frequencies We will calculate the cumulative frequencies for each age group: - For 20-25: 110 - For 25-30: \( 110 + x \) - For 30-35: \( 110 + x + 75 = 185 + x \) - For 35-40: \( 185 + x + 55 = 240 + x \) - For 40-45: \( 240 + x + y \) - For 45-50: \( 240 + x + y + 30 = 270 + x + y \) ### Step 4: Use the Median Formula The formula for median is given by: \[ \text{Median} = L + \left( \frac{N/2 - F}{f} \right) \times H \] Where: - \( L \) = lower limit of the median class = 30 - \( N \) = total frequency = 400 - \( F \) = cumulative frequency of the class preceding the median class = \( 110 \) (for 20-25) - \( f \) = frequency of the median class = 75 - \( H \) = class width = \( 35 - 30 = 5 \) Substituting the values into the formula: \[ 32 = 30 + \left( \frac{200 - (110)}{75} \right) \times 5 \] \[ 32 - 30 = \left( \frac{90 - x}{75} \right) \times 5 \] \[ 2 = \left( \frac{90 - x}{75} \right) \times 5 \] \[ 2 = \frac{90 - x}{15} \] Multiplying both sides by 15: \[ 30 = 90 - x \] Rearranging gives: \[ x = 90 - 30 = 60 \] ### Step 5: Find the Value of \( y \) The total frequency must equal 400: \[ 110 + x + 75 + 55 + y + 30 = 400 \] Substituting \( x = 60 \): \[ 110 + 60 + 75 + 55 + y + 30 = 400 \] Calculating the left side: \[ 330 + y = 400 \] Solving for \( y \): \[ y = 400 - 330 = 70 \] ### Step 6: Calculate \( x - y \) Now we can find \( x - y \): \[ x - y = 60 - 70 = -10 \] ### Final Answer The value of \( x - y \) is \(-10\). ---

To solve the problem, we need to find the values of \( x \) and \( y \) from the given age distribution and then calculate \( x - y \). ### Step 1: Identify the Median Class The median age is given as 32, which lies in the age group 30-35. Therefore, the median class is 30-35. ### Step 2: Write Down the Given Frequencies The frequency distribution is as follows: - Age (in years): 20-25, 25-30, 30-35, 35-40, 40-45, 45-50 ...
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