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The mean of a certain number of observa...

The mean of a certain number of observations is m. If each observation is divided by `x(ne 0)` and increased by y, then

A

`mx+y`

B

`(mx+y)/(x)`

C

`(m+xy)/(x)`

D

`m+xy`

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The correct Answer is:
To solve the problem step by step, we will derive the new mean when each observation is divided by \( x \) (where \( x \neq 0 \)) and then increased by \( y \). ### Step 1: Understand the Mean The mean \( m \) of a set of observations \( x_1, x_2, \ldots, x_n \) is given by the formula: \[ m = \frac{\sum_{i=1}^{n} x_i}{n} \] This implies: \[ \sum_{i=1}^{n} x_i = m \cdot n \] ### Step 2: Transform the Observations According to the problem, each observation \( x_i \) is transformed by dividing it by \( x \) and then adding \( y \). Thus, the new observations can be represented as: \[ \text{New observation} = \frac{x_i}{x} + y \] ### Step 3: Calculate the New Mean The new mean \( \text{New Mean} \) can be calculated as follows: \[ \text{New Mean} = \frac{\sum_{i=1}^{n} \left(\frac{x_i}{x} + y\right)}{n} \] ### Step 4: Simplify the New Mean We can separate the terms in the numerator: \[ \text{New Mean} = \frac{\sum_{i=1}^{n} \frac{x_i}{x} + \sum_{i=1}^{n} y}{n} \] Since \( y \) is a constant, we can simplify further: \[ \text{New Mean} = \frac{\frac{1}{x} \sum_{i=1}^{n} x_i + n \cdot y}{n} \] ### Step 5: Substitute the Old Mean Now, substituting \( \sum_{i=1}^{n} x_i = m \cdot n \): \[ \text{New Mean} = \frac{\frac{1}{x} (m \cdot n) + n \cdot y}{n} \] This simplifies to: \[ \text{New Mean} = \frac{m}{x} + y \] ### Step 6: Combine the Terms We can express this as: \[ \text{New Mean} = \frac{m + xy}{x} \] ### Final Result Thus, the new mean after transforming the observations is: \[ \text{New Mean} = \frac{m + xy}{x} \]
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OBJECTIVE RD SHARMA ENGLISH-MEASURES OF CENTRAL TENDENCY-Chapter Test
  1. The arithmetic mean of ""^(n)C(0),""^(n)C(1), ... ,""^(n)C(n), is

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  2. The arithmetic mean of the squares of first n natural numbers is

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  3. Geometric mean of 3, 9 and 27, is

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  4. If for a moderately skewed distribution, mode = 60 and mean = 66, then...

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  5. the median of 10, 14, 11, 9, 8, 12, 6 is

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  6. The mean of discrete observations y(1), y(2), …, y(n) is given by

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  7. The average of 50 numbers is 38. If the numbers 45 and 55 are disca...

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  8. The geometric mean of numbers 7, 7^(2),7^(3),…,7^(n), is

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  9. The sum of deviations of n observations about 25 is 25 and sum of devi...

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  10. If the sum of the mode and mean of a certain frequency distribution i...

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  11. The mean weight of 9 items is 15. If one more item is added to the ser...

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  12. The mode of the data 6,4,3,6,4,3,4,6,3,x can be

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  13. If the difference between the mode and median is 2, then the differen...

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  14. If the mean of the following distribution is 13, then p = {:(x(i) :...

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  15. The mean of a certain number of observations is m. If each observati...

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  16. The frequency distribution of marks obtained by 28 students in a test ...

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  17. If the median of (x)/(2),(x)/(3),(x)/(4),(x)/(5),(x)/(6) ("where " x...

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  18. If the median of the scores 1,2,x,4,5("where " 1 lt 2 lt x lt 4 lt 5) ...

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  19. Mode of a certain series is x. If each score is decreased by 3, then ...

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  20. If the median of 33 ,\ 28 ,\ 20 ,\ 25 ,\ 34 ,\ x\ i s\ 29 , find th...

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