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The value of int x log x (log x - 1) dx ...

The value of `int x log x (log x - 1) dx ` is equal to

A

`2(xlogx-x)^(2)+C`

B

`(1)/(2)(xlogx-x)^(2)+C`

C

`(x logx)^(2)+C`

D

`(1)/(2)(x logx)^(3)+C`

Text Solution

Verified by Experts

The correct Answer is:
b
Let `I=intx logx (logx-1)dx=intlogx(xlogx-x)dx`
`rArrI=int(xlogx-x)d (xlogx-x)=((xlogx-x)^(2))/(2)+C`
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