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Let F(x)=f(x) g(x) h(x) for all real x, ...

Let `F(x)=f(x) g(x) h(x)` for all real x, where f(x), g(x), and h(x) are differentiable functions. At some point `x_(0),F'(x_(0))=21F(x_(0)),f'(x_(0))=4f(x_(0)),g'(x_(0))=-7g(x_(0)), and h'(x_(0))=kh(x_(0)).` Then k = -

A

12

B

12

C

24

D

-24

Text Solution

Verified by Experts

The correct Answer is:
C

We have,
`F(x)=f(x)g(x)h(x)`
`implies" "logF(x)=logf(x)+logg(x)+logh(x)`
Differentiating both sides w.r.t. x, we get
`(F'(x))/(F(x))=(f'(x))/(f(x))+(g'(x))/(g(x))+(h'(x))/(h(x))`
`implies" "(F'(x_(0)))/(F(x_(0)))=(f'(x_(0)))/(f(x_(0)))+(g'(x_(0)))/(g(x_(0)))+(h'(x_(0)))/(h(x_(0)))`
`implies" "21=4-7+lambda`
`implies" "lambda=24`
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