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For the curve x = t^2 - 1, y = t^2 - t, ...

For the curve `x = t^2 - 1, y = t^2 - t,` the tangent line is perpendicular to `x`-axis, then `t =` (i)`0` (ii)`infty` (iii) `1/(sqrt3)` (iv) `-1/(sqrt3)`

A

`t=0`

B

`t=oo`

C

`t=1//sqrt(3)`

D

`t=-1//sqrt(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
we have,
`x=t^(2)-1, y=t^(2)-t`
`therefore (dy)/(dx)=((dy)/(dt))/((dx)/(dt))=(2t-1)/(2t)`
If the tangent is perpendicular to x-axis, then
`(dx)/(dy)=0 rArr (2t)/(2t-1)=0rArr t=0`
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OBJECTIVE RD SHARMA ENGLISH-TANGENTS AND NORMALS-Chapter Test
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  2. The abscissa of the point on the curve ay^(2)=x^(3), the normal at whi...

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  3. If the curves (x^2)/(a^2)+(y^2)/(b^2)=1 and (x^2)/(l^2)-(y^2)/(m^2)=1c...

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  4. The length of normal at any point to the curve, y=c cosh(x/c) is

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  5. If the sub-normal at any point on y=a^(1-n)x^(n) is of constant length...

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  6. The angle of intersection of the curves y=x^(2), 6y=7-x^(3) at (1, 1),...

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  7. The slope of the tangent to the curve x=t^2+3t-8,\ \ y=2t^2-2t-5 at ...

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  8. What is the angle between these two curves x^3-3xy^2+2=0 and 3x^2y-y^3...

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  9. about to only mathematics

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  10. If y=4x-5 is a tangent to the curve y^(2)=px^(3)+q at (2, 3), then:

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  11. The curve y-e^(xy)+x=0 has a vertical tangent at the point:

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  12. The tangent to the curve given by x = e^(t) cos t y = e^(t) " sin t ...

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  13. The length of the normal at t on the curve x=a(t+sint), y=a(1-cos t), ...

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  14. For the parabola y^(2)=4ax, the ratio of the subtangent to the absciss...

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  15. The length of the subtangent to the curve sqrt(x) +sqrt(y)=3 at the po...

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  16. Find the euation of normal to the curve x=a( cos theta + theta sin th...

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  17. Tangents ar drawn to y= cos x from origin then points of contact for t...

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  18. If m denotes the slope of the normal to the curve y= -3 log(9+x^(2)) a...

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  19. If m be the slope of the tangent to the curve e^(2y) = 1+4x^(2), then

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  20. If the curve y=ax^(3) +bx^(2) +c x is inclined at 45^(@) to x-axis at...

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  21. If the curve y=ax^(2)+bx+c passes through the point (1, 2) and the lin...

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